c^2-10c+12=0

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Solution for c^2-10c+12=0 equation:


Simplifying
c2 + -10c + 12 = 0

Reorder the terms:
12 + -10c + c2 = 0

Solving
12 + -10c + c2 = 0

Solving for variable 'c'.

Begin completing the square.

Move the constant term to the right:

Add '-12' to each side of the equation.
12 + -10c + -12 + c2 = 0 + -12

Reorder the terms:
12 + -12 + -10c + c2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -10c + c2 = 0 + -12
-10c + c2 = 0 + -12

Combine like terms: 0 + -12 = -12
-10c + c2 = -12

The c term is -10c.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10c + 25 + c2 = -12 + 25

Reorder the terms:
25 + -10c + c2 = -12 + 25

Combine like terms: -12 + 25 = 13
25 + -10c + c2 = 13

Factor a perfect square on the left side:
(c + -5)(c + -5) = 13

Calculate the square root of the right side: 3.605551275

Break this problem into two subproblems by setting 
(c + -5) equal to 3.605551275 and -3.605551275.

Subproblem 1

c + -5 = 3.605551275 Simplifying c + -5 = 3.605551275 Reorder the terms: -5 + c = 3.605551275 Solving -5 + c = 3.605551275 Solving for variable 'c'. Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + c = 3.605551275 + 5 Combine like terms: -5 + 5 = 0 0 + c = 3.605551275 + 5 c = 3.605551275 + 5 Combine like terms: 3.605551275 + 5 = 8.605551275 c = 8.605551275 Simplifying c = 8.605551275

Subproblem 2

c + -5 = -3.605551275 Simplifying c + -5 = -3.605551275 Reorder the terms: -5 + c = -3.605551275 Solving -5 + c = -3.605551275 Solving for variable 'c'. Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + c = -3.605551275 + 5 Combine like terms: -5 + 5 = 0 0 + c = -3.605551275 + 5 c = -3.605551275 + 5 Combine like terms: -3.605551275 + 5 = 1.394448725 c = 1.394448725 Simplifying c = 1.394448725

Solution

The solution to the problem is based on the solutions from the subproblems. c = {8.605551275, 1.394448725}

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